STRAIN ENERGY
When a body is in a state of stress loaded
externally deformation takes place a simple tensile member tends to elongate
and a compressive member shortens the ratio of change in length to the original
length is called strain since strain is a ratio of two lengths it is a
dimensionless quantity.
Thus the tensile or compressive strain is given byStrain = change in length/original length
e = δl/l
Shear strain:Consider a block is rigidly fixed to a vertical surface and force ‘p’ acts along its top fact tangentially to the top face under the action of shear force the block.
Shear strain Φ = BB’/AB = x/y
Since ‘x’ will be small therefore Φ is expressed in radians thus the measure of shear strain is the rotation of the planes perpendicular to the applied shear load.
Volumetric strain:Consider each face of a cube is subjected to equal compressive force. The result of this force will be reduction in volume the ratio of change in volume to the original volume is called volumetric strain.
Volumetric strain = change in volume/ original volume
e =δv/v
Suppose the original length of each side of the cube is L and δl is the decrease in length of each side due to stress then
Volumetric strain = L³ – (L – δl) ³/L³
Neglecting small quantities,
Volumetric strain = 3³ l.δl/L³ =3.δl/L
ev =3.e
Volumetric strain is equal to three times the linear strain.
STRAINS ENERGY:When a force is applied to an elastic body it causes a linear deformation and as a result of this deformation the point of application of a force undergoes a displacement. Thus the work is done by a force this work is stored in the elastic body as strain energy. When external force is removed this stored energy takes back the material to original position according to the principle of conservation of energy the work done by external force is equal to strain energy.
Resilience:Strain energy stored within the elastic limit is called resilience.
Proof resilience:The maximum energy stored within the elastic limit is called proof resilience it is the strain energy corresponding to stress at elastic limit.
Modulus of resilience:The proof resilience per unit volume of a body is called modulus of resilience.
Strain
energy:
Consider a body of cross-sectional area a and
length l is subjected to a tensile load p. let ‘δl’ be the extension of the bar
the work done by the load is represented by shaded area of load extension
diagram.
Thus strain energy U = Work done
= ½ P.δl
= ½ f.A.
f.l/E
= f²/2E.A.l
U
= f²/2E.V Nmm
Where f = stress induced in the body, N/mm²
V = Volume of the body,
mm³
E = modulus of elasticity, N/mm²
If
‘fe’ is the stress induced at elastic point.
Then
proof resilience =f²e/2E V N.mm
And
modulus of resilience = f²e/2E N/mm³.
Alternate expression:
U =½ P.δl
δl = Pl/AE
U = P²l/2AE
Strain energy for different modes of loads:
The
load P can be applied to the body in three different ways
1. Gradually applied load
2. Suddenly applied load
3. Falling or impact load
Gradually applied load:
In this case load increases gradually from zero to
final value therefore the average load is considered to calculate the strain
energy consider an elastic body of uniform cross-section of length l is
subjected to gradually apply tensile load.
Let δl =
extension of the bar
Work done =
average load x extension
=(o+p/2)δl
=pδl/2
From principle of conservation of energy.
Work done =
strain energy
p δl/2 = σ²/2E
Al
p σl/2E =
σ²/2E Al
Thus σ
= P/A N/mm²
Where P
= load applied N
A =
cross-sectional area, mm²
U = σ²/2E Al
Nmm²
Where σ
= stress induced N/mm².
E = modulus of
elasticity N/mm².
A =cross-sectional
area mm².
l = length of
bar mm.
Suddenly applied load:
In this case load acts instantly on a body and the
extension takes place at a constant load. P
Work done by load =
load x extension
=p x δl
Strain energy:
σ². Al/2E
Work done =
strain energy
p. δl = σAl²/2E
p .σ.l/E =
σ²Al/2E
(OR) σ – 2P/A
Falling or impact load:
In this case load dropped from a certain height
before it stretch the bar consider a load p falls from a height h on a collar
which is attached to the lower end of the bar let δl be the extension of the
bar under impact load.
Work done =
P(h+δl)
strain energy stored = σ².Al/2E
Since W.D.is equal to strain energy stored
therefore
p(h++δl) = σ².Al/2E
ph+p.σl/E = σ².Al/2E
ph= σ².Al/2E- p.σl/E
Multiplying both sides by 2E/Al.
2E ph/Al =
σ²-2pσ/A
Solving the above quadratic equation σ = 2p/A±√4p²/A²+4.2Eph/Al
σ = p/A±√p²/A²+2Eph/Al
σ = p/A+√(p/A)²+2Eph/Al
The above equation gives the stress induced due to
falling load a after calculating the value of stress the corresponding strain
energy may be calculated.
Salience: strain energy stored
within elastic limiter.
Proof resilience: maximum strain energy
stored within elastic limit.
Modulus of resilience: proof resilience per unit
of volume of bar.
1.
General expression for strain energy.
Strain energy,
u = σ². Al/2E
2.
Stress induced in gradually applied load.
σ = 2p/A
3.
Stress induced in suddenly applied load.
σ = 2p/A
4.
Stress induced due to impact load.
σ =
p/A+√(P/A)²+2Eph/Al
If maximum extension is negligible then.
σ = √2Eph/Al
5.
Stress induced due to sudden stopping of mss m moving with a velocity V
σ = √E.m.V²/Al
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